Consider this data. 10 (s) 2.7418 T 185.37 L 186.21 (cm) 2.7412 (s) 186.51 186.4

Question

Consider this data. 10 (s) 2.7418 T 185.37 L 186.21 (cm) 2.7412 (s) 186.51 186.476 186.75 S 186.66 (cm) 186.96 0.444577 186.8 S 186.57 (cm) 186.35 0.140588 186.58 2.7415 0.000424 0.0003 The following analysis will include calculating and formally reporting the best estimate of the acceleration due to gravity according to the following formula. 2 With accepted value, gace -980.35 cm/s2 Ready to be the teacher? List everything that is wrong with the following portion of an analysis. (If you would like to use a red pen, feel free!) In the end, you formally report what the result should be. (Hint: There are two missing elements in the error propagation term so two sets of empty parentheses are there to help you spot where they are.) -)10537 185.37 cm g = 973.6944 cm/s2

Explanation / Answer

In error propagation term :-

1) Value of SL has to be larger due to air drag force .

2) Value of ST has to be smaller due to air drag force and string mass .

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