Please explain how they got the sum of the potential energies. ( step by step pl
ID: 1421909 • Letter: P
Question
Please explain how they got the sum of the potential energies. ( step by step please )
A system consist of the charges -q at (-d,0), +2q at (d,0), and +3q at (0,d). What is the total electrical potential energy of the system? Write the electric potential energy between -q and +2q: -kq(29)/ad Write the electric potential energy between -q and +3q: -kq(3q)/squareroot2d Write the electric potential +2q and +3q: k(2q)(3q)/squareroot 2d Sum the contribution from each pair of charges to find the total electrical potential energy: U=3kq^2/squareroot 2d - kq^2/dExplanation / Answer
electric potential energy of the system = electric potential energy between the three charges
Electric potential energy of the system = PE12 + PE13 + PE23
= k(-q)(2q) / 2d + k(-q)(3q) / sqrt2 d + 3kq^2 / sqrt 2 d
= 3 kq^2/sqr2 d - kq^2/d
= kq^2/d ( 3/sqrt2 - 1)
= 1.12 kq^2/d