The Mirror Equation and Questions 6 Through 10 For the next few questions, go to
ID: 1423086 • Letter: T
Question
The Mirror Equation and Questions 6 Through 10 For the next few questions, go to the PhET optics simulation (http//phet Colorado edu/sims/geometric optics/geometric optics_en html) The object is the one you move, on the left Its image is on the right There is a relationship between the object distance (d_0, distance between object and lens center), image distance (d_i, distance between lens center and image), and focal length of a lens It says that: 1/d_o+1/d_i=1/f Measure the initial values of these 3 distances (d_0,d_i and f) on your screen, and record them below Using your three measured values above, show that when you plug these values into the formula above, the left side of the equation equals the right side When the object is outside of the focal length on the left side of the converging lens, describe the image [List whether it is upside down or right-side-up. real or virtual, and larger or smaller ] When the object is inside the focal length of the lens, what type of image would be formed (real or virtual)?Explanation / Answer
The image formed is inverted and real and on other side of the object when the object is placed infront of the converging lens and out side of the focal point.
the size of the image is greater than the object when the object is placed between f and 2f. the size of the image is smaller than the object when the object placed ouside the 2f. (f is focal lenght)
the image formed is virtual, and upright whne the object placed before the focal point. the size of the image greater than that of object.