Plus-minus A simple Network of Capacitors (Figure 1) In the figure are shown thr

Question

Plus-minus A simple Network of Capacitors (Figure 1) In the figure are shown three capacitors with capacitances C_1=6.00 muF, C_2=3.00 muF, C_3=5.00 muF. The capacitor network is connected to an applied potential V_ab. After the changes on the capacitors have reached their final values, the charge Q_2 on the second capacitor is 40.0 muC. Part A what is the charge Q_1 on capacitors C_1? Q_1= Mu^C Part B What is the charge on capacitor C_3? Express your answer in microcoulombs tothree significant figures. Q_3= muC Part C What is the applied voltage, V_ab? Express your answer in volts to three significant figures. V_ab= V

Explanation / Answer

charge on C2, Q2 = 40 uC

C2 = 3 uF

Q2 = C2 V2

V2 = 40 / 3 Volt

potential diff across C1 and C2 will be same as they are connected in parallel.

V1 = V2 = 40/3 volt

charge on C1, Q1 = C1V1 = 6 x 40/3 = 80 uC .....Ans(A)

b) charge on C3 , Q3 = Q1 + Q2 = 40 + 80 = 120 uC

c) Vab = V1 + V3

V3 = Q3/C3 = 120 / 5 = 24 volt

Vab = (40/3) + 24   = 37.33 Volt

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