The diploid number of a hypothetical animal is 2n=16. Each diploid cell contains
ID: 142739 • Letter: T
Question
The diploid number of a hypothetical animal is 2n=16. Each diploid cell contains 12ng of DNA in G1. Mow many ng of DNA would be in each cell A. Immediately after S phase B. Durring mitotic metaphase C. Durring meiotic prophase I D. Durring meiotic prophase IIThe diploid number of a hypothetical animal is 2n=16. Each diploid cell contains 12ng of DNA in G1. Mow many ng of DNA would be in each cell A. Immediately after S phase B. Durring mitotic metaphase C. Durring meiotic prophase I D. Durring meiotic prophase II
A. Immediately after S phase B. Durring mitotic metaphase C. Durring meiotic prophase I D. Durring meiotic prophase II
Explanation / Answer
The diploid number of a hypothetical animal is 2n=16.
Each diploid cell contains 12ng of DNA in G1.
So Immediately after S phase, the amount of DNA would be 24 ng, (Immediately after the S phase all of the chromosomes have been effectively replicated, i.e., each chromosome has two (sister) chromatids; so the amount of DNA in the cell has effectively doubled, although the ploidy of the cell remains the same.)
During mitotic metaphase 24 ng, (During metaphase chromosomes gets condensed and align themselves in the equator of the cell before being separated into each of the two daughter cells.)
During meiotic prophage I 24 ng (To enter meiosis I, a cell must first go through interphase, where during G1 phase the cell grows, S phase the DNA is replicated and in G2 the cell prepares for divisionAt the beginning of Prophase I where recombination of chromosomes take place, the DNA content of the cell is double than a non-dividing cell but the chromosome number is same)
During meiotic prophase II 12 ng per cell respectively.( In prophase II the nucleoli and the nuclear envelope disappears and the chromatids condenses, and prepares them for second meiotic division.)