Physics 2020 nm wst Your name the capacitor will be 2 How many estra electross w
ID: 1427480 • Letter: P
Question
Physics 2020 nm wst Your name the capacitor will be 2 How many estra electross will be on theevpe of h 3 You have 4 equal poist charges say 2 C at the 4coes of sreif y 4. Suppose all is the same as in).esrept that ehe (hargewi (1,-1+m)" Use superposition to find the tela ow at (ur1- S. How much work must be done to asserable the oar charge aay is Esm 6. A 1 and 3 resistor are connected in series aross the 60 volt battery. How many electrens er second pass throngh the luttery . To turn a galvanometer into a voltmeter I penerally havet a) provide a low shat resistanc, a, paralel with the meter b) previde a high shunt resistance in series with the e c) provide a low series resistance in parallel with the tr d) provide a high seres resistance in in parallel with the i8 with the meter 8. IfI insert a slab of dielectric material between the plates of ahd capacitor I will usually A) reduce B) increave C) not change the voltage between the platesExplanation / Answer
1) Q = CV = 6*10^-6*50 = 300 uC
2) As Q = ne ====> n = Q/e = 300*10^-6/1.6*10^-19 = 1.875*10^11 electrons.
3) As the distance from each charge is same, so due to symmetry net electric field will be zero at centre of square.
4) Then electric field will be in same direction due to charges at (1,1) and (-1,-1),so the field will be sum up.
E = 2kq/r^2 = (2*9*10^9*2*10^-6)/1.414^2 = 18000 N/C (towards -ve charge)
5) Due to symmetry, work done will be zero.
6) R = 1 + 2 + 3 = 6 ohm
Then I = V/R = 6/6 = 1 A = 1 C/s = 6.25*10^18 electrons per second.
7) Add a suitable high resistance in series with galvanometer.
8) V reduce as V = Q/C and C = kC0 where k is dielectric constant.