Please show work when selecting answer. A 2.00 kg block with a speed of 3.00 m/s
ID: 1429083 • Letter: P
Question
Please show work when selecting answer.
A 2.00 kg block with a speed of 3.00 m/s collides with a 10.0 kg block that has a speed of 1.00 m/s in the same direction. After the collision, the 10.0 kg block is observed to be traveling in the original direction with a speed of 1.80 m/s. What is the velocity (speed and direction) of the 2.00 kg block immediately after the collision?
{Assume no friction, as the law of conservation of linear momentum can only be applied if all external forces on the isolated system are 0.}
a) 1.20 m/s in the opposite direction
b) 1.00 m/s in the opposite direction
c) 2.42 m/s in the same direction
d) 0.580 m/s in the same direction
SHOW YOUR WORK PLEASE
a) 1.20 m/s in the opposite direction
b) 1.00 m/s in the opposite direction
c) 2.42 m/s in the same direction
d) 0.580 m/s in the same direction
SHOW YOUR WORK PLEASE
Explanation / Answer
use conservation of momentum:
m1*v1i + m2*v2i = m1*v1f + m2*v2f
2* 3 + 10*1 = 2*v + 10*(1.8)
6 + 10 = 2*v + 18
v = - 1 m/s
negative sign shows that direction will be opposite
Answer: b