Plz be accurate with decimals don\'t round it. I need 3 decimals if applicable F
ID: 1429461 • Letter: P
Question
Plz be accurate with decimals don't round it. I need 3 decimals if applicableFlying Circus of PhysicS The figure shows a swimmer at distance D = 40.0 m from a lightning strike to the water, with current 1 82.0 kA. The water has resistivity 30 -m, the width of the swimmer along a radial line from the strike is 0.600 m, and his resistance across that width is 5.00 k2. Assume that the current spreads through the water over a hemisphere centered on the strike point. What is the current through the swimmer? Units Number the tolerance is +/-9%
Explanation / Answer
We know thatcurrent density J = I/A
I = lightening current at strike point = 82kA = 82000Amps
A = area of hemisphere = 2?D2
D = 40 m
Then A = 2?(40m)2
Then current density J = I/A =82000Amperes/2?(40m)2= 8.16 A/m2
Now width of the swimmer is ?r = l = 0.6 m
resitivity of water ? = 30?m
area of the swimmer be A'
resistence of the swimmer is R = 5k? = 5000ohm
Then R = ?l/A'
5000 =(30?m)(0.6m)/A'
Then A '= 0.0036m2
Then current through the swimmer is I ' = J*A' = (8.16A/m2)*0.0036m2 = 0.029376Amperes
answer -------------------- 0.029376 A