All work please: a swimmer tries to cross a river at the angle theta to the perp
ID: 1432009 • Letter: A
Question
All work please: a swimmer tries to cross a river at the angle theta to the perpendicular to the stream . (to the left). the speed of the swimmer is v, the speed of the river is u. the width of the river is d. at what point of the other shore will the swimmer land (calculate the distance d between landing point and the opposite point. All work please: a swimmer tries to cross a river at the angle theta to the perpendicular to the stream . (to the left). the speed of the swimmer is v, the speed of the river is u. the width of the river is d. at what point of the other shore will the swimmer land (calculate the distance d between landing point and the opposite point. All work please: a swimmer tries to cross a river at the angle theta to the perpendicular to the stream . (to the left). the speed of the swimmer is v, the speed of the river is u. the width of the river is d. at what point of the other shore will the swimmer land (calculate the distance d between landing point and the opposite point.Explanation / Answer
Speed Perpendicular to the stream, = v*cos()
Speed Parallel to the stream, = v*sin()
Net speed Parallel to the stream, = v*sin() + u
Time taken to cross width, t = d/(v*cos())
Total Distance travelled, parallel to stream in the same time, d = (v*sin() + u) * d/(v*cos())
Distance between the landing point and the opposite point, = sqrt[ ((v*sin() + u) * d/(v*cos()))^2 + (d)^2 ]
Net Speed = sqrt(v*cos())^2 + (v*sin() + u)^2]