In the figure below, a magnetic field of 0.7 Tesla points into the page. A parti

Question

In the figure below, a magnetic field of 0.7 Tesla points into the page. A particle of charge -28 nC and mass 0.3 ?g is shot into the field as shown in the figure with a velocity of 0.3 km/s. What is the radius of the orbit (in meters)? (The radius is a positive quantity.) Be careful with the powers of 10. Hint: k=kilo, m=milli, ?=micro, n=nano and the SI units for magnetic field, charge, mass, length and time are: tesla (T), coulomb (C), kilogram (kg), meter (m) and second (s), respectively. Do not include units with your answer.

Explanation / Answer

apply centripetal force = magnetic force

i.e mv^2/r = qvB,

so speed v = 300 m/s

where m = mass o the charged particle = 0.3 e -9 kgs

r = radius ,

q = charge = 1.6*10^-19 C

B = magnetic field

so now , so as r = mv/qB

r = (0.3 e -9 * 300)/(28 e -9 * 0.7)

r = 4.59 m (ANSWER)

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