In a Young\'s double-slit experiment, a set of parallel slits with a separation

Question

In a Young's double-slit experiment, a set of parallel slits with a separation of 0.100 mm is illuminated by light having a wavelength of 551 nm and the interference pattern observed on a screen 4.00 m from the slits.

(a) What is the difference in path lengths from the two slits to the location of a fifth order bright fringe on the screen? Incorrect: Your answer is incorrect. µm

(b) What is the difference in path lengths from the two slits to the location of the fifth dark fringe on the screen, away from the center of the pattern? µm

Explanation / Answer

(a) The path difference to the 5th bright fringe is 5

Now, = 5.51x10^-7 m

Therefore, path difference to the 5th order bright fringe = 5x5.51x10^-7 =  2.755 x 10^-6 m = 2.755 µm

(b) The path difference to the 5th dark fringe is 4½ (in between n=4 and 5 bright fringes)

So path difference = 4½ x (551^-9m) = 2.479x10^-6m = 2.479 µm

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