In (Figure 1) , R1 = 2.0 , R2 = 1.5 , R3 = 2.0 , R4 = 1.0 , R5 = 2.0 , R6 = 1.0

Question

In (Figure 1) , R1 = 2.0 , R2 = 1.5 , R3 = 2.0 , R4 = 1.0 , R5 = 2.0 , R6 = 1.0 , C1 = 10 F , C2 = 70 F , E = 11 V . Assume that the circuit has been connected for several minutes. https://session.masteringphysics.com/problemAsset/1924760/3/Mazur1e.ch31.p76.jpg

Part A

Calculate the current through the battery.

Part B

Calculate the current through the resistor R1.

Part C

Calculate the current through the resistor R2.

Part D

Calculate the current through the resistor R3.

Part E

Calculate the current through the resistor R4.

Part F

Calculate the current through the resistor R5.

Part G

Calculate the current through the resistor R6.

Part H

Compute the magnitude of charge on each plate of the capacitor C1.

Part I

Compute the magnitude of charge on each plate of the capacitor C2.

Explanation / Answer

part A)

current through battery = V/R = 11/[ R1||R2 +R4+R5+R6] = 11/[2*1.5/(2+1.5) +1+2+1] = 11/4.857 = 2.265A

Part B

the current through the resistor R1 =[potential across R1||R2]/R1 = [2.265A *2*1.5/(2+1.5) ] / 2 = 0.971 A

Part C

the current through the resistor R2 = [potential across R1||R2]/R2 = [2.265A *2*1.5/(2+1.5) ] /1.5 = 1.294 A

Part D

the current through the resistor R3 = 0 because there is a capacitor

Part E

the current through the resistor R4 = 2.265A because all the current will flow through R4

Part F

the current through the resistor R5=2.265A because all the current will flow through R5

Part G

the current through the resistor R6=2.265A because all the current will flow through R6

Part H

magnitude of charge on each plate of the capacitor C1 = C1* [potential across R1||R2]

=10*[2.265*2*1.5/(2+1.5) ] C

=19.4  C

Part I

magnitude of charge on each plate of the capacitor C2 = C2* [potential across R4+R5+R6]

= 70*[2.265*(1+2+1) ] C   = 634.2 C

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