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Assume the resistance values are R 1 = 2,300 , R 2 = 1,600 , R 3 = 4,600 , and R

ID: 1439544 • Letter: A

Question

Assume the resistance values are

R1 = 2,300 , R2 = 1,600 , R3 = 4,600 , and R4 = 5,900 ,

and the battery emfs are



Use Kirchhoff's rules to analyze the circuit in the figure below.

(a) Let I1 be the branch current though R1, I2 be the branch current through R2, and I3 be the branch current through R3. Write Kirchhoff's loop rule relation for a loop that travels through battery 1, resistor 1, and resistor 3. (Use a clockwise current loop when entering your answer. Use any variable or symbol stated above as necessary.)

1I1R1I3R3

  = 0

(b) Write Kirchhoff's loop rule relation for a loop that travels through battery 2, resistor 2, and resistor 3. (Use a clockwise current loop when entering your answer. Use any variable or symbol stated above as necessary.)

2+I3R3I2R2

= 0

(c) Apply Kirchhoff's junction rule to the junction at A to get a relation between the three branch currents. (Use any variable or symbol stated above as necessary.)
I1 =

I2+I3


(d) You should now have three equations and three unknowns (I1, I2, and I3). Solve for the three branch currents.

The answers for a, b, and c are correct. I need help solving for I1 I2 and I3 using those equations.

I1 =  A I2 =  A I3 =  A

Explanation / Answer

here,

1I1R1I3R3 = 0 ------------(1)
2+I3R3I2R2 = 0 ------------------(2)
I1 = I2+I3 ----------(3)

Using 3 in 1, we get,
(I2+I3)*r1 + I3*R3 = E1

I2*R1 + I3 (R1 + R3) = E1
I2*2300 + I3 (2300 + 4600) = 1.5
I2*2300 + I3*6900 = 1.5 ----------(4)


also Second Eqn Cna be written as,

I2*1600 - I3*4600 = -3 --------------(5)

Comparing 4 and 5, we have two varibale solving for I2 , I3,

Using 5 as I2 = ((-3 + I3*4600)/1600) in 4 we get,

((-3 + I3*4600)/1600)*2300 + I3*6900 = 1.5
upon solvign we get,

I3 = 0.0004 A -------------------------------------(6)

Using I3 in eqn 4 to get value of I2,

I2*1600 - 0.0004*4600 = -3
I2 = -0.0007 A --------------------------------------(7)

Therefore From Eqn 3,

I1 = I2 + I3
I1 = -0.0007 + 0.0004
I1 = -0.0003 A -------------------------------------------(8)

Please check your value of Resistances given in question( They are really high ) , they seems wrong to me,