Car enthusiasts often lower their cars closer to the ground as a matter of style
ID: 1442472 • Letter: C
Question
Car enthusiasts often lower their cars closer to the ground as a matter of style. James wants to lower his car by replacing all four of his original coil springs with new ones offered as an option by the car manufacturer.* In science, we try to represent complex systems with simplified representations. The new springs will be identical to the original springs except the force constant will be 4655.00 N/m smaller. When he removes the original springs he discovers that the length of each spring expands from 8.55 cm (its length when installed) to 12.00 cm (its length with no load placed on it). If the mass of the car body is 1155.00 kg, how much lower will the body drop compared to its original height?
Car enthusiasts often lower their cars closer to the ground as a matter of style. James wants to lower his car by replacing all four of his original coil springs with new ones offered as an option by the car manufacturer. In science, we try to represent complex systems with simplified representations. The new springs will be identical to the original springs except the force constant will be 4655.00 N/m smaller. When he removes the original springs he discovers that the length of each spring expands from 8.55 cm (its length when installed) to 12.00 cm (its length with no load placed on it). If the mass of the car body is 1155.00 kg, how much lower will the body drop compared to its original height? Number c m James was hoping for an overall lowering by 7 cm. Which of the following most closely describes James' results? uamesweuhfor an overall owering by 7 am. Which of the folowing most dlosely describers The change is too drastic, causing the O car to be un-driveable. James will be mostly pleased with the The change is so small that James has O results largely wasted his time and moneyExplanation / Answer
Each spring bore F = mg/4 = 1155*9.8/4 = 2830 N
The compression was x = 12 - 8.55 = 3.45 cm = 0.0345m,
from hooks law F =kx
k = F / x = 2830 / 0.0345 = 82029 N/m
The new springs have stiffness k = (82029 - 4655) = 77374 N/m
and will compress x = F / k = 2830 / 77374 = 0.0369 m = 3.66 cm
Correct opiton is the change is too drastic, causing the car to be undriveable