Assume the wire visible in the plane is bent perpendicularly at A and at C, with

Question

Assume the wire visible in the plane is bent perpendicularly at A and at C, with the remainder of the wire behind the paper. A current of 8.26 A flows toward you at A, through the visible portion, and back in the opposite direction at C. Consider the wires below the plane at A and C to be semi-infinite. What is the magnitude of the magnetic field at the center of the arc O due to the current in the wire? It may be necessary to take into account the contribution from the long straight wire which runs up to and down from the plane of the page. The permeability of free space is 1.25664 x 10^-6 T. m/A. Answer in units of T.

Explanation / Answer

here,

the magnitude of magnetic feild due to the straight wire at centre is zero

current , I = 8.26 A

then

magnetic feild due to arc , B = ( theta/360) * u0 * I /(2*r)

B = ( 90/360) * ( 1.26 * 10^-6 * 8.26)/(2*8)

B = 1.63 * 10^-7 T

the magnetic feild at the centre of arc is 1.63 * 10^-7 T

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