I\'m stuck on part d!!! Two identical spheres of mass, m, hanging from threads o
ID: 1443847 • Letter: I
Question
I'm stuck on part d!!!
Two identical spheres of mass, m, hanging from threads of length, L, repel each other after being given identical charges of q as shown below. Without assuming specific values for any variables, derive an expression for the charge q. For the remaining parts of this question, assume that m = 3.0g,L=1.5m, and theta = 12degree. What is the charge q ? Assuming the spheres are negatively charged, how many excess electrons does each have? If the spheres are made of aluminum, what is the ratio of the number of excess electrons of either sphere to the total number of electrons of that sphere?Explanation / Answer
(d)
mass of sphere = 3.0 g
No of electrons in 1 atom of Al = 13
No of atoms = 3.0/26.982 * 6.023 *10^23 atoms
Total No of Electrons on Sphere, = 3.0/26.982 * 6.023 *10^23 * 13
Total No of Electrons on Sphere, = 8.71 * 10^23 electrons.
Now you divide your answer of part (c) with the above calculated value to get the ratio.