Consider the three circuits shown above. All the resistors and all the batteries
ID: 1444308 • Letter: C
Question
Consider the three circuits shown above. All the resistors and all the batteries are identical. (For each statement select T True, F False). The current through a resistor is the same in circuits A and B. The total power dissipated in circuit C is twice the total power dissipated in circuit B. The power dissipated in circuit A is twice the power dissipated in circuit B. The voltage across a single resistor in circuit C is twice the voltage across a single resistor in circuit B. The current through a resistor is the same in circuits A and C.Explanation / Answer
A)
F
in circuit A , Total resistance = R , in circuit B , Total resistance = 2R
since the two circuits have different total resistances, the battery provides different current in each circuit.
B)
F
Power dissipated in B
Pb = V2/2R
Power dissipated in C
Pc = V2/R + V2/R = 2V2/R
hence Pc is double not of Pb
c)
T
power dissipated in A = Pa = V2/R
Power dissipated in B
Pb = V2/2R
hence Pa = 2Pb
d)
T
In B , The total Voltage V is equally divided between two resistances , hence
Voltage across each resistance in B = V/2
in C , the two resistances are in parallel , hence they each have same Voltage across them
Voltage across each resistance in C = V
clearly Voltage across each in C = 2 x Voltage across each resistance in B
E)
T
current through R in A = V/R
in C , each resistor have Voltage V across them , so current in each using ohm's law = V/R