A 120 g ball moving to the right at 4.5 m/s catches up and collides with a 450 g

Question

A 120 g ball moving to the right at 4.5 m/s catches up and collides with a 450 g ball that is moving to the right at 1.1 m/s. If the collision is perfectly elastic, what is the speed of the 120 g ball after the collision? Express your answer to two significant figures and include the appropriate units. If the collision is perfectly elastic, what is the direction of motion of the 120 g ball after the collision? If the collision is perfectly elastic, what is the speed of the 450 g ball after the collision? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

assume right side is positive

m1 = 120 gm = 0.120 kg

v1i = 4.5 m/s

m2 = 450 g= 0.450 kg

v2i = 1.1 m/s

v1f = [(m1-m2)*v1i/(m1+m2) ] + 2m2*v2i / (m1+m2)

v1f = -0.868 m/s = -0.87 m/s

here negative sign means ball is moving in opposite direction

part b )

to left

part c )

v2f = [2m2*v1i/(m1+m2)] + (m2-m1)*v2i/(m1+m2)

v2f = 7.74 m/s = 7.7m/s

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