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Part 1 of 2 - Force between two current carrying wires Two parallel wires separa

ID: 1446771 • Letter: P

Question

Part 1 of 2 - Force between two current carrying wires Two parallel wires separated by a distance of d=1.00 cm are carrying currents of h = 3.00 A and 12-1.50 A in opposite directions as shown. Answer the following questions. Question 1 of 6 5.0 Poin What are the magnitude and direction of the magnetic field created by l1 at the location of l2? O A. 6.00 x 10- T, out of page B. There is no magnetic field at the location of l2 C. 6.00x 10 5 T, into page D. 3.00 × 10-5 T, into page E.3.00x 10 T, out of page Reset Selection 5.0 Poin Question 2 of 6 What are the magnitude and direction of the magnetic field created by /2 at the location of 1? A. 1.50 x 10-5 T out of page B. There is no magnetic field at the location of C. 3.00x105 T out of page D. 1.50 x 105 T into page 0 E. 3.00 × 10-5 T into page

Explanation / Answer

Magnetic field due to a long current carrying conductor = 2kI/a

1. Magnetic field by I1 at I2 = 2kI1/d = 2*10^-7*3/0.01 = 6*10^-5 T
From right hand rule, into the paper is the direction of the field
hence option C

2. Magnetic field by I2 at I1 = 2kI2/d = 2*10^-7*1.5/0.01 = 3*10^-5 T
From right hand rule, into the paper is the direction of the field
hence option E

3. F/l = 2k*I1*I2/d = 2*10^-7*3*1.5/0.01 = 9*10^-5 N
opposite direction of current, so repulsive force
hence option A