In the Atwood machine shown below, m1 = 2.00 kg and m2 = 8.00 kg. The masses of
ID: 1449418 • Letter: I
Question
In the Atwood machine shown below, m1 = 2.00 kg and m2 = 8.00 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.60 m/s downward.
(a) How far will m1 descend below its initial level?
_________
(b) Find the velocity of m1 after 1.80 s.
________ Direction? Upward, downward or velocity is zero?
Please give units and explanations as well as stating the answer. Double check work. Thanks
Explanation / Answer
lighter mass willl have acc. upward and heavier mass will have acc. upward a.
on lighter mass m1:
T - m1g = m1a ........(i)
on m2:
m2g - T = m1a ..........(ii)
(i) + (ii) =>
m2g - m1g = (m1 + m2)a
a= 9.8 ( 8 - 2) / (8 +2) = 5.88 m/s^2
a) initial speed, u = - 2.60 m/s^2
a = + 5.88 m/s^2
using v^2 - u^2 = 2ad
0^2- 2.60^2 = 2 ( 5.88)(d)
d = 0.575 m downward
b) v = u + at
v = -2.60 + (5.88)(1.80)
v = 7.98 m/s upward