Can i please get help with this question. Thank you so much. Two people carry a

Question

Can i please get help with this question.

Thank you so much.

Two people carry a heavy electric motor by placing it on a light board 2.50 m long. One person lifts at one end with a force of 420 N, and the other lifts the apposite end with a force of 700 N. What is the weight of the motor? Where along the board is its center of gravity located? Suppose the board is not light but weighs 220 N, with its center of gravity at its center, and the two people each the same the same forces as before. What is the weight of the motor in this case? Where is its center of gravity located?

Explanation / Answer

Part-A : The weight of the motor which is given as -

w = F1 + F2 = (420 N) + (700 N)

w = 1120 N

Part-B : The board is its center of gravity located at a distance which is given as -

using a condition of torque, we have

F1 . x = F2 . (2.5 m - x)

(420 N) x = (700 N) [(2.5 m - x)]

(420 N) x = (1750 N.m) - (700 N) x

x = (1750 N.m) / (1120 N)

x = 1.56 m

{ from the end where the (420 N) force is applied }

Part-C : The weight of the motor in this case which is given as -

w = F1 + F2 - F0 = (420 N) + (700 N) - (220 N)

w = (1120 N) - (220 N)

w = 900 N

Part-D : It's center of gravity located at a distance which is given as -

using a condition of torque, we have

F1 . x + (F0 / 2) (2.5 m) = F2 (2.5 m - x) + F0 x

x = (2.5 m) [F2 - (F0 / 2)] / F1 + F2 - F0

x = (2.5 m) [(700 N) - (110 N)] / (420 N) + (700 N) - (220 N)

x = (1475 N.m) / (900 N)

x = 1.63 m

{ from the end where the (420 N) force is applied }

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