If the generation rate for a contaminant is 12 mg/min and the dilution flow rate
ID: 1455941 • Letter: I
Question
If the generation rate for a contaminant is 12 mg/min and the dilution flow rate is 2,000 CFM, what is the equilibrium concentration of the contaminant, in mg/m^3? This is very easy. The equilibrium concentration, C_eq, is the generation rate, G, divided by the volume flow rate, Q. C_eq = G/Q = 12mg/min/2000ft^3/min (0.0353 ft^3/l)(10^3l/m^3) = 0.212/m^3 The generation rate for a contaminant is 25 mg/min. The dilution volume flow rate is 4,000 CFM. What is the equilibrium concentration of the contaminant in mg/m^3?Explanation / Answer
equilibrium concentration of contaminant = G/Q
= (25/4000) * (0.0353ft3/l) * (103l/m3)
= 0.2206 mg/m3