Problem 2 (10 POINTS) A particle with charge q = 8.7 x 10^-6C is moving with vel
ID: 1457797 • Letter: P
Question
Problem 2 (10 POINTS) A particle with charge q = 8.7 x 10^-6C is moving with velocity vector v = 8.3 x 10^3ms^-1 hat y in a uniform, constant, magnetic field vector B. The magnetic force on the particle is measured to be vector F = -6.7 x 10^-3 N hat x + 2.5 x 10^-3 N hat z. (a) Calculate all the components of the magnetic field vector B that can be determined from this information. Problem 3 (10 POINTS) Two very long (infinity) parallel wires, d = 0.5m apart, carry currents I1 = 15A. an = 25A, respectively, in the same direction hat z, see figure.Explanation / Answer
q = 8.7*10^-6 C
Am representing unit vector along x -direction as i
Am representing unit vector along y -direction as j
Am representing unit vector along z -direction as k
v = 8.3*10^3 j
F =-6.7*10^-3 i + 2.5*10^-3 k
F =q(v x B)
Let us consider B = Bxi+Byj+Byk
-6.7*10-3 i + 2.5*10-3 k= (8.7*10-6)[(8.3*103j) x (Bxi+Byj+Bzk)]
-6.7*10-3 i + 2.5*10-3 k= (8.7*10-6) [-(8.3*103 )Bx k +(8.3*103)Bz i]
-6.7*10-3 i + 2.5*10-3 k= -(72.21*10-3)Bx k +(72.21*10-3)Bz i
Comparing both sides of i aand k components
-6.7*10-3 =72.21*10-3 Bz
Bz = - 0.0928 T
2.5*10-3 k= -72.21*10-3 Bx
Bx = -0.0346 T
By = 0
Bz = - 0.0928 T