Refer to the circuit in the figure below, a solenoid is connected to an emf with
ID: 1462903 • Letter: R
Question
Refer to the circuit in the figure below, a solenoid is connected to an emf with a switch. When the switch is closed, current begins to flow through the circuit. Initially, the current increases (it has to increase because it was initially zero). After some amount of time, the current reaches steady-state and is then constant. If the switch is then opened, the current decreases back to zero. Assume that the circuit itself, and the line passing through the center of the solenoid, are in the plane of the page (so that the plane of the coils making up the solenoid are perpendicular to the page). So, when viewed from the right, you can see straight down the center of the solenoid and current runs clockwise through it. The position of three different loops are shown in the figure. For the problem, assume that the three loops shown are all oriented in the same direction as the solenoid. Now we close the switch, wait until the current reaches steady-state, and then open the switch again.
a) Determine the direction of the current induced in each loop (when viewed from the right) while the current is still increasing after the switch is closed.
b) Determine the direction of the current induced in each loop (when viewed from the right) after the current has reached steady-state after the switch is closed.
c) Determine the direction of the current induced in each loop (when viewed from the right) while the current is still decreasing if the switch is opened
3 2Explanation / Answer
A)The direction of the current induced in each loop (when viewed from the right) while the current is still increasing after the switch is closed
By ampere law and right hand rule the magnetic field of line goes rom right to left
If the current is increasing so does the magnetic field increases in both loop 1 and loop 2
but in the loop 3 it decreses . So the induced current will try to oppose the change so the current will flow in anti clock wise direction in loop 1& 2 while Clockwise in Loop 3
Loop 1= anti clock wise direction
Loop 2= anti clock wise direction
Loop 3= clock wise direction
B) the direction of the current induced in each loop (when viewed from the right) after the current has reached steady-state after the switch is closed.
If it is in steady state then tere is no change in magnetic flux so no current/emf is induced
Loop 1= no current
Loop 2= no current
Loop 3= no current
C)The direction of the current induced in each loop (when viewed from the right) while the current is still decreasing if the switch is opened
It is just the opposite of the first case ,here there is decrese in the magnetic flux ,in this case the current s will be as follows
Loop 1= clock wise direction
Loop 2= clock wise direction
Loop 3= anti clock wise direction