Consider the conductor and current in Example 27.8 in the textbook, but now let

Question

Consider the conductor and current in Example 27.8 in the textbook, but now let the magnetic field be parallel to the x-axis.

Part A

What is the magnitude of the total magnetic force on the conductor?

Express your answer in terms of the variables B, L, I, and R.

F =

Part B

What is the diraction of the total magnetic force on the conductor?

+x-direction

x-direction

+y-direction

y-direction

+z-direction

z-direction

Part C

In Example 27.8 in the textbook, the total force is the same as if we replaced the semicircle with a straight segment along the x-axis. Is that still true when the magnetic field is in this different direction?

Part D

Explain why, or why not?

Explanation / Answer

Part A:

The magnitude of the total magnetic force on the conductor

F = ILB

Part B

Along the x-axis, the force on straight section is zero. The net force on he semicircular section is zero since for the half of the semicircle at negative x the force is out of the page and another half of the semicircle at positive x the force is into the page. The net field is cancelled and remains zero.

The force on the straight section that is perpendicular to the plane of the figure is in the negative y-direction

Answer:     y-direction

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Part C and Part D:

In the case of semicircular section is replaced by a straight section along the x -axis, then the magnetic force on that straight section would be zero. It is the same as it is for the semicircle. In this case, also net force is zero as mentioned in the pervious case.

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