In the figure below, two blocks, of mass m1 = 220 g and m2 = 620 g, are connecte
ID: 1468163 • Letter: I
Question
In the figure below, two blocks, of mass m1 = 220 g and m2 = 620 g, are connected by a massless cord that is wrapped around a uniform disk of mass M = 500 g and radius R = 12.0 cm. The disk can rotate without friction about a fixed horizontal axis through its center; the cord cannot slip on the disk. The system is released from rest. (a) Find the magnitude of the acceleration of the blocks. m/s2 (b) Find the tension T1 in the cord at the left. N (c) Find the tension T2 in the cord at the right. N
Explanation / Answer
Here ,
let the acceleration of the blocks is a
Using second law of motion
acceleration ,a = net force/effective mass
a = (m2 - m1) * g/(m1 + m2 + I/R^2)
a = (0.62 - 0.22 ) * 9.8/(0.22 + 0.62 + 0.5 * 0.5 )
a = 3.6 m/s^2
the acceleration of the blocks is 3.6 m/s^2
b)
tension in the left cord
T1 - m1 * g = m1 * a
T1 = 0.22 * ( 9.8 + 3.6)
T1 = 2.95 N
the tension T1 in the cord at the left is 2.95 N
c)
at the tension in right cord
m2 * g - T2 = m2 * a
T2 = 0.62 * (9.8 + 3.6)
T2 = 8.31 N
the tension T2 in the cord at the right is 8.31 N