Map this question has been customized by sapling learning Angela Reisetter at ve

Question

Map this question has been customized by sapling learning Angela Reisetter at versity of Evansville termine the image distance for an object do 6.500 cm from a diverging lens where both sides have the same radius of curvature 5.200 cm, and the lens has an index of refraction 1.850. (Express your answer as a positive quantity.) Number cm R 5.200 cm object What is the magnification of the object? (Be sure to insert the proper sign, or do Number What is the nature of the image? O Inverted and smaller O Upright and smaller O Inverted and larger O Upright and larger

Explanation / Answer

R = radius of curvature = 5.200 cm

n = refractive index of lens = 1.850

focal length of lens is given as

1/f = (n - 1) (-2/R)

1/f = (1.850 - 1) (-2/5.2)

f = - 3.1 cm

do = object distance = 6.5 cm

using lens equation

1/f = 1/do + 1/di

1/(-3.1) = 1/6.5 + 1/di

di = - 2.1 cm

image distance = 2.1 cm

magnification = m = - di/do = - (-2.1) / 6.5 = 0.323

upright and smaller

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