Part A On January 22, 1943, the temperature in Spearfish, South Dakota, rose fro
ID: 1472630 • Letter: P
Question
Part A
On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -3.80 F to 45.2 F in just 2 minutes. What was the temperature change in Celsius degrees and in kelvins?
Answer in the order indicated. Separate your answers using comma.
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Part B
The temperature in Browning, Montana, was 44.0 F on January 23, 1916, and the next day it plummeted to -55.8 F. What was the temperature change in Celsius degrees and in kelvins?
Answer in the order indicated. Separate your answers using comma.
TC,TK = C,KExplanation / Answer
Ti = - 3.80 F
Tf = 45.2 F
in degree Celcius :
Ti = (-3.80 - 32 ) (5/9) = - 19.88 C
Tf = (45.2 - 32 ) (5/9) = 7.33 C
change in temperature = 7.33 - (-19.88) = 27.21
In Kelvin :
Ti = (-3.80 - 32 ) (5/9) + 273.15 = 253.27
Tf = (45.2 - 32 ) (5/9) + 273.15 = 280.48
change in Temperature = 280.48 - 253.27 = 27.21
part B)
Ti = 44 F
Tf = - 55.8 F
in degree Celcius :
Ti = (44 - 32 ) (5/9) = 6.67 C
Tf = (- 55.8 - 32 ) (5/9) = - 48.78 C
change in temperature = - 48.78 - (6.67) = - 55.45
In Kelvin :
Ti = (44 - 32 ) (5/9) + 273.15 = 279.82 C
Tf = (- 55.8 - 32 ) (5/9) + 273.15 = 224.4 C
change in Temperature = 224.4 - 279.82 = - 55.42