Can someone please explain the answer for 2c? A capacitor is connected to an AC

Question

Can someone please explain the answer for 2c? A capacitor is connected to an AC voltage source which generates rms voltage VAC at frequency A schematic of the circuit is shown here: (1 pt.) As increases, the capacitor's reactance (impedance) will: increase decrease remain unchanged (1 pt.) As VM increases, the capacitor's reactance (impedance) will: increase decrease remain unchanged (1 pt.) If the AC voltage source were replaced by a DC voltage source (like a battery), the capacitor's reactance (impedance) would become. Zero infinite the same as its impedance for an AC frequency of 60 Hz

Explanation / Answer

a) B) decrease

beacsue, capacitive reactance, XC = 1/(2*pi*f*C)

so, As f inceases XC decreases.

b) C)remain unchanged

XC depends only on c and f. it does not depnd on emf of the source.

c) B) infinite

for dc, f = 0

so, XC = 1/(2*pi*0*C)

= inifinte

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