A 55-kg box rests on the horizontal surface. The coefficient of static friction

Question

A 55-kg box rests on the horizontal surface. The coefficient of static friction between the box and the service is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface? Express your answer using two significant figures. A 55-kg box rests on the horizontal surface. The coefficient of static friction between the box and the service is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface? Express your answer using two significant figures.

Explanation / Answer

mass, m = 55.0 Kg
Static Fricition, us = 0.30
Kinetic Friction, uk = 0.20

To start Sliding along the Surface we need to overcome, Static Friction.
Horizontal Force to be applied to start Sliding -
F = us * m*g
F = 0.3 * 55 * 9.8 N
F = 161.7 N

F = 1.6 * 10^2 N

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