It is necessary to show all clear and complete details of your work. Data: G = 6

Question

It is necessary to show all clear and complete details of your work. Data: G = 6.67 times 10^-11 Nm^2/Kg^2; g = 9.8 m/s^2 F = GM1M2/R^2; W = mg Vav = 1/2(v0 + v); Delta x = x0 + v0t + 1/2 at^2 Sigma F = ma; f = muN; Delta x = Vav - t v^2 = v0^2 + 2a Delta x; Theta = tan^-1(y/x), V0x = V0cosTheta, V0y = V0sinTheta a = v^2/r; Compute the vertical component of force Compute the horizontal component of force Compute the acceleration of the block along the floor Determine the speed of the block after moving 12s Calculate the distance traveled by the block m 12 s Calculate the total distance covered in the 12s

Explanation / Answer

a)Vertical Component of force applied is 1300 Sin30 = 650 N

b) Horizontal component of applied force is 1300 Cos 30 = 1125.83 N

c) a = Fh/m = 1125.83/170 = 6.622 m/s2

d) v = a*t = 6.622*12 = 79.47 m/s

e) Distance travelled is s = 1/2 *g*t^2 = 0.5*9.8*12^2 = 705.6 m

f) Total distace covered is also 705.6 m

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