Can someone explain this to me step by step please? Thank you! A ladybug sits at

Question

Can someone explain this to me step by step please?

Thank you!

A ladybug sits at the outer edge of a merry-go-round of radius 2.50 m, and a gentleman bug sits halfway between her and the axis of rotation. The merry-go-round starts from rest, and accelerates uniformly for 30.0 seconds. It then rotates uniformly at a rate of 2.00 revolutions per minute. The bugs remain at rest with respect to the merry-go-round. At any given instant in time, the gentleman bug's tangential velocity is half the ladybug's. the same as the ladybug's. squareroot 2 times the ladybug's. twice the ladybug's. During the first 30.0 seconds of motion, the angular acceleration of the ladybug is 8.55 x 10^-4 rad/s^2 3.12 x 10^-3 rad/s^2 6.98 x 10^-3 rad/s^2 1.40 x 10^-2 rad/s^2 2.76 x 102 rad/s^2 During the first 30.0 seconds of motion, the direction of the acceleration of the gentleman bug at the instant shown in the diagram to the right is A B C D E

Explanation / Answer

31. A ..............angular velocity =wR

32. angular acceleration = w/t =6.98*10^-3

33. B

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