In the figure below, the mass M_1=8.51 kg and angle theta =20.5 degrees.Between
ID: 1491770 • Letter: I
Question
In the figure below, the mass M_1=8.51 kg and angle theta =20.5 degrees.Between the block M1 and inclined plane the coefficent of static friction is mu_s=0.350 and the coefficent of kinetic function mu_i=0.220. The system of block initially at rest. A) Draw Free bedy diagrams for beth blocks B)Using the forces you indicated on your diagrams in A) write down the equation for Newton's second law in the x and y direction for M_1 and in the y direction for M_2 C) what is the minimum value of M_2 required to start M_1 moving up the incline? M_2 is now incrensed to 10.2 kgExplanation / Answer
Since you have done the remaining parts, I am starting from part d
writing equation for M2
M2 a = M2 g - T
10.2a = 10.2*9.8 - T
10.2a = 99.96 -T ........EQUATION 1
and writing equation the along the incline
T- M1 g sin 20.5 - u M1 g cos 20.5 = M1 a
8.51a = T - 8.51*9.8*0.35 - 0.22*8.51*9.8*0.937
8.51a = T - 46.38............EQUATION2
adding equation 1 and 2,
(8.51+10.2)a = 99.96 -T +T - 46.38 =53.58
a = 53.58/(8.51+10.2)
a = 2.8637 m/s^2
E) since both masses are string constrained, their speeds and acceleration magnitudes are same
v^2 = u^2 +2as
= 0 + 2*2.8637*2 =11.4548
v = sqrt 11.4548 = 3.38 m/s