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I\'m not sure how to solve this problem. I\'m give f=60 Hz Time for one rotation

ID: 1493145 • Letter: I

Question


I'm not sure how to solve this problem. I'm give f=60 Hz
Time for one rotation is 1/60 sec. Cos changed to 2. The equation at the top is voltage=BA ( cos theta) / change in time. In a 1/2 turn cos theta changes by 2 + time= 1/120 sec

20 Points i 20 Points rotio A 200-turn loop of radius 1.0 current. Th fot e current in the wire is reduced to zero in 0.3 seconds cm is 50 cm from a very long straight wire carrying 250 mA of 2o State very clearly why a voltage will be induced in the coil. 200 turn call 250mA Determine the magnitude of the induced voltage State very clearly the direction of current flow in the coil. You must give your reasoning for the direction you chose

Explanation / Answer

here,

number of turns , n = 200

radius , r = 0.01 m

current , I = 0.25 A

time taken , t = 0.3 s

as the current changes in the wire ,

the magnetic feild due to wire changes so that the magnetic flux through the loop also change with respect to time

as, EMF induced = change in flux /time

there is some EMF induced

magnetic feild due to wire , B = u0 * I /( 2*pi*d)

EMF = n * area * B /t

EMF = n * pi * r^2 * (u0 /(2*pi*d*t)) * ( I - 0)

EMF = 200 * pi * 0.01^2 * ( 1.26 * 10^-6 /(2*pi*0.5*0.3)) * 0.25

EMF = 2.1 * 10^-8 V

as the current is decreasing in the wire ,

the magnetic flux is decreasing due to wire

using Lenz's law

the induced current is so that the flux is increased

so, the direction of current in the loop is counterclockwise