I\'m not sure how to solve this problem. I\'m give f=60 Hz Time for one rotation
ID: 1493145 • Letter: I
Question
I'm not sure how to solve this problem. I'm give f=60 Hz
Time for one rotation is 1/60 sec. Cos changed to 2. The equation at the top is voltage=BA ( cos theta) / change in time. In a 1/2 turn cos theta changes by 2 + time= 1/120 sec
Explanation / Answer
here,
number of turns , n = 200
radius , r = 0.01 m
current , I = 0.25 A
time taken , t = 0.3 s
as the current changes in the wire ,
the magnetic feild due to wire changes so that the magnetic flux through the loop also change with respect to time
as, EMF induced = change in flux /time
there is some EMF induced
magnetic feild due to wire , B = u0 * I /( 2*pi*d)
EMF = n * area * B /t
EMF = n * pi * r^2 * (u0 /(2*pi*d*t)) * ( I - 0)
EMF = 200 * pi * 0.01^2 * ( 1.26 * 10^-6 /(2*pi*0.5*0.3)) * 0.25
EMF = 2.1 * 10^-8 V
as the current is decreasing in the wire ,
the magnetic flux is decreasing due to wire
using Lenz's law
the induced current is so that the flux is increased
so, the direction of current in the loop is counterclockwise