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In the diagram is shown an RL circuit with a switch. ? = 90.0 V , R 1 = 25.0 ? ,

ID: 1496690 • Letter: I

Question

In the diagram is shown an RL circuit with a switch. ? = 90.0 V, R1 = 25.0 ?, R2 = 50.0 ? and L = 45.0 H. Find the values of i1, the current through resistor R1 and i2, the current through resistor R2, the current through the switch, the potential difference across R2, the potential difference across L and the rate of change of the current di2/dt in the time just after the closing of the switch.

10 parts (3 unanswered)

1) What is i1 just after the switch is closed?
3.60 A

2) What is i2 just after the switch is closed?
0.00 A

3) What is the value of the current in the switch just after the switch is closed?
3.60 A

4) What is the the potential difference across R2 just after the switch is closed?
0.00 V

5) What is the the potential difference across L just after the switch is closed?
9.00×101 V

6) What is i1 a long time after the switch is closed?

UNANSWERED

7) What is i2 a long time after the switch is closed?

UNANSWERED

8) What is the value of the current in the switch a long time after the switch is closed?
5.40 A

9) What is the the potential difference across R2 a long time after the switch is closed?

UNANSWERED

10) What is the the potential difference across L a long time after the switch is closed?
0.00 V

2

Explanation / Answer

Here,

E = 90V

R1 = 25 Ohm

R2 = 50 Ohm

L = 45 H

1)

just after closing the switch

inductor will bahave as an open circuit

i1 = E/R1

i1 = 90/25 A

i1 = 3.75 A

the current i1 is 3.75 A

2) as just after closing the switch

inductor will bahave as an open circuit

the current in R2 is zero
3)

current in switch = current in R1 + current in R2

current in switch = 3.75 + 0

current in switch = 3.75 A

4)
as the current through R2 is zero

potential across R2 = R2 * 0

potential across R2 = 0 V

5)

as the potential difference across indutor

potential difference across inductor = E

potential difference across inductor = 90 V

the potential difference across inductor is 90 V
6) a long time after the switch is clsoed

inductor will bahave as short circuit

i1 = E/R1

i1 = 90/25 A

i1 = 3.75 A

the current i1 is 3.75 A

7)

a long time after the switch is clsoed

inductor will bahave as short circuit

i2 = E/R2

i2 = 90/50 A

i2 =1.8 A

the current in resistance R2 is 1.8 A