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I posted this question once already and got mostly wrong answers and am complete

ID: 1498717 • Letter: I

Question

I posted this question once already and got mostly wrong answers and am completely stumped on where to go from here.

Jigsaw Puzzle | disney I 52 × % Physics 210-HW#8-Spr × P Pandora Radio-Lister WX V e Chegg Study | Guided So -> c Dwww.webassign.net/web/Student/Assignment-Responses/last?dep=13657069 × 5. +1.5/6.75 points | Previous Answers My Notes Ask Your Teacher (Note: Please be careful with roundoff error in this problem.) The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 2.1 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 5.6 kg and is initially at rest. After the collision, the two pucks fly apart with the angles shown in the drawing 65 +5.5 mis 37 At rest Before collision After col lision (a) Find the final speed of: puck A: 2.2 puck B: 1.24 m/s m/s (b) Find the kinetic energy of the A+B system: before the collision: 31.76 after the collision: 9.38 What type of collision is this? somewhat inelastic Submit Answer Save Pr 6. -1 points My Notes Ask Your Teacher You are holding a shopping basket at the grocery store with two 0.55 kg cartons of cereal at one end of the basket. The basket is 0.76 m long. Where should you place a half gallon ETO12:01 PM

Explanation / Answer

ma = 2.1 Kg
vai = 5.5 m/s
vaf = ?

mb = 5.6 Kg
vbi = 0
vbf = ?

Using Momentum conservation,
In X Direction,
ma * vai + mb * vbi = ma*vaf*cos(65) + mb * vbf * cos(37)  
2.1 * 5.5 + 0 = 2.1 * vaf * cos(65) + 5.6 * vbf * cos(37) -----1

In Y Direction,
0 = ma*vaf*sin(65) - mb * vbf * sin(37)  
2.1 * vaf * sin(65) = 5.6 * vbf * sin(37) -----2

Solving eq 1 & 2,
vaf = 3.38 m/s
vbf =  1.91 m/s


(b)
K.E before Collision = 1/2*ma * vai^2 +1/2* mb * vbi^2
K.E before Collision = 1/2*2.1*5.5^2 + 1/2*5.6*0
K.E before Collision =  31.76 J

K.E after Collision = 1/2*ma * vai^2 +1/2* mb * vbi^2
K.E after Collision = 1/2*2.1*3.38^2 + 1/2*5.6*1.91^2
K.E after Collision = 22.21 J

Kinetic Energy is not conserved.
Type of Collision, Somewhat Inelastic.

I hope this solution helps you !!