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Refer to the diagram (not to scale), which shows a sphere (of outer radius R) th

ID: 1498960 • Letter: R

Question

Refer to the diagram (not to scale), which shows a sphere (of outer radius R) that is made of solid glass except for a spherical cavity at its center (of radius R/3), which is empty. The sphere carries a total net charge of -Q that is uniformly distributed throughout the glass (but no charge resides in the empty central cavity). In terms of R, Q, K (or E_0), find an expression for the electric field (magnitude and direction)-as a function of distance r from the sphere's center-for the following regions: 0 inequality r

Explanation / Answer

a)


consider a gaussian sphere of radius r < R/3

charge inside = Qin = 0

from gauss law

total flux = Qin/eo

total flux = E*A = E*4*pi*r^2

E*4*pi*r^2 = 0/eo


E = 0


++++++++++++

(b)

charge density sigma = Q/(4/3*pi*(R^3-(R/3)^3)

sigma = Q/(4/3*pi*(26/27)*R^3)


consider a gaussian sphere of radius R/3 < r < R

effective volume V = 4/3*pi*(r^3-(R/3)^3)) = (4/3)*pi*(r^3-R^3/27)

charge inside Qin = sigma*V = sigma* (4/3)*pi*(r^3-R^3/27)

from gauss law

total flux = Qin/eo

total flux = E*A = E*4*pi*r^2

E*4*pi*r^2 = sigma*(4/3)*pi*(r^3-R^3/27)/eo


E*r^2 = ((1/3)*(Q/(4/3*pi*(26/27)*R^3))*(r^3-(R^3/27)))/eo

E = Q*(27r^3-R^3)/(4*pi*26*R^3*r^2)


(c)

consider a gaussian sphere of radius r > R


charge inside Qin = Q

from gauss law

total flux = Qin/eo

total flux = E*A = E*4*pi*r^2

E*4*pi*r^2 = Q/eo


E = Q/(4*pi*r^2)