In the circuit shown in the following figure(Figure 1) the capacitor has capacit
ID: 1501991 • Letter: I
Question
In the circuit shown in the following figure(Figure 1) the capacitor has capacitance 19 mu F and is initially uncharged. The resistor R_0 has resistance 12 Ohm. An emf of 89.0 V is added in series with the capacitor and the resistor. The emf is placed between the capacitor and the switch, with the positive terminal of the emf adjacent The switch is closed at t = 0. When the current in the large circuit is 4.20, A, what is the magnitude of the induced current in the small circuit? Express your answer to two significant figures and include the appropriate units. What is the direction of the induced current in the small circuit? clockwise counterclockwiseExplanation / Answer
Let the area of the bigger circuit be A. the are of the smaller circuit is ab. If the current induced in the smaller circuit be i, then i/ab = 4.2/A. so i = 4.2ab/A A