Additional Materials

Question

Question Part Points Submissions Used

Question Part Points Submissions Used

Question Part Points Submissions Used

Question Part Points Submissions Used Question Part Points Submissions Used (a) At what location on the level 1 rod should the free end of rod 2 be attached?
L1 =

(b) At what location on the level 2 rod should the free end of rod 3 be attached?
L2 =

(c) At what location on the level 3 rod should the whole assembly be suspended from so that the mobile is in equilibrium?
L3 =

Question Part Points Submissions Used

Explanation / Answer

The first part (a) is half-way of the distance so (a) is 37.5 cm

we need to attach each part at its center of mass.

Part (b) will be 133*1 + 133 * 75 + 133 * (75 +37.5) all divided by 3 * 133 then subtract the first part (37.5).

So. it is 27.33 cm

Part (c) will be 133*1 + 133 * 75 + 133 * (75 +37.5) all divided by 3 * 133 then subtract the first part (37.5).

So. it is 27.33 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---