Torque & Moment of inertia Data collected: Please also show the equation used to
ID: 1504846 • Letter: T
Question
Torque & Moment of inertia
Data collected:
Please also show the equation used to solve the values, I need it for excel
Part B) Why is the graph a parabola?
Plot both experimental and theoretical moments of inertia against r
The rotational motion apparatus is given a constant torque by mean of tension exerted by a falling mass of 150 g (equivalent to a force of HH 1.47 N applied tangentially to the vertical shaft . To calculate that torque, you will need to measure the diameter r , of the shaft. The moment of inertia of the spinning part can be changed by positioning masses on the threaded rod, at a distance r from the shaft. For this experiment, four moments of inertia will be considered: lo with no mass attached to the threaded rod I5 with 200 g on each opposite sides, 5 cm from the axis of rotation Iho with 200 g on each opposite sides, 10 cm from the axis of rotation I5 with 200 g on each opposite sides, 15 cm from the axis of rotation & Measure the diameter and note the radius of the rotating shaft: ro = _IDS Set a meter stick next to the hanging mass so that a vertical drop of 50 cm can easily be measured to each moment inertia to determine, rewind the apparatus, time and record the vertical drop of For of the hanging mass in the data table Calculate velocities of hanging mass in each case and use kinematic equations for average linear the uniform acceleration final velocity Vmax and aavg. these values to compute the average acceleration Add to the data table.Explanation / Answer
Part A) As, Torque = Moment of inertia * angular acceleration
=> Force * radius = Moment of inertia * angular acceleration
=> Itheorotical = (1.47 * 0.6 * 10-2)/8.45
= 1.0437 * 10-3 kg.m2
=> Itheorotical = (1.47 * 0.6 * 10-2)/4.81
= 1.8336 * 10-3 kg.m2
=> Itheorotical = (1.47 * 0.6 * 10-2)/2.05
= 4.3024 * 10-3 kg.m2
=> Itheorotical = (1.47 * 0.6 * 10-2)/0.92
= 9.5869 * 10-3 kg.m2
Part B) Moment of inertia = 1/2 * M * R2
=> moment of inertia is directly proportional to square of Radius .
=> graph is a parabola .