Map deb sapling learning Event A happens at the spacetime coordinates (1 ghtseco

Question

Map deb sapling learning Event A happens at the spacetime coordinates (1 ghtsecond (ls) is the distance light moves in 1 second) A, xA, y A (8.50 s, 8.90 ls, 1.30 ls, 8.40 ls) in the frame S, and event B happens at the spacetime coordinates, ('s, x's, y's, z's)- 35.2 s, 44.6 s, 130 ls, 8.40 ls in another frame S', which is moving along the +x-axis at a speed u- 0.930c relative to the frame S. Calculate the time interval between events A and Bin frame S, and in frame S' Number 17.10 Incorrect. Number This is the time when event B occurs in frame S. 35.807 O In frame S, event A happens first then B, while in frame S'it is the opposite. O In both frames S and S, event A happens first then B. O n both frames Sand S', event B happens first then A. O n frame S, event B happens first then A, while in frame S'it s the opposite.

Explanation / Answer

t = t0/(1-v2/c2)1/2

t = time observed in the other reference frame

t0 = time in observers own frame of reference (rest time)

v = the speed of the moving object

c = the speed of light in a vacuum

NOw ta = 8.5 s....

tb' = -35.2

tb = tb' * sqrt(1-v/c ^2) = -35.2 * sqrt(1- 0.93^2) = -12.938 s

so tb - ta = -21.438

now in S' frame..:.

tb' = -35.2

ta=8.5

so ta' = ta*sqrt(1-v/c ^2) = 8.5* sqrt(1-0.93^2) = 3.12425 s

so tb' - ta' = 38.3245

ta=8.5 tb = -12.938 in S frame.... so B occurs first...........

ta' =3.1245 and tb' = -35.2   in S' frame.... so here also B occurs first....

so in both frames event B happpens first and then A

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