In the circuit depicted, an ideal battery is connected to five resistors whose v

Question

In the circuit depicted, an ideal battery is connected to five resistors whose values are give. The battery voltage is given too. Compare the magnitudes of the currents I_2 + I_5 through the resistors R_2 + R_5, respectively. Calculate the total power, P_1 delivered to the circuit by the batter. -p = 15.0 w -p = 20.0 w -p = 21.6 w -p = 36.0 w -p = 64.8 w Batteries that aren't ideal have non-zero internal resistances. It the ideal battery in the above circuit is replaced with a non-ideal battery having the same voltage rating, the current I_1 through resistor R_1 will decreases.

Explanation / Answer

Equivalent esistance of the circuit,
Req = R1 + R2 || (R3 +R4 +R5)
Req = 15 + 30 || (5 + 5 + 5)
Req = 15 + 30 || (15)
Req = 15 + (30*15)/(30+15)
Req = 25

I2 * R2 = I5 * (R3 +R4 +R5)
I2 * 30 = I5 * 15
I2 * 2 = I5

So,
I2 < I5

Power dissipated = V^2/Req
P = 30^2/ 25 W
P = 36.0 W

As I = V/Req
By adding internal resistance we would increase the resistance of the circuit, therefore Current would decrease so

True

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