A heavy ball is dropped into a lake from a height of 30.0 m above the water. It

Question

A heavy ball is dropped into a lake from a height of 30.0 m above the water. It hits the water with a certain velocity and continues to sink to the bottom of the lake at this same constant velocity. It reaches the bottom of the lake 10.0 s after it was dropped. How deep is the lake? A heavy ball is dropped into a lake from a height of 30.0 m above the water. It hits the water with a certain velocity and continues to sink to the bottom of the lake at this same constant velocity. It reaches the bottom of the lake 10.0 s after it was dropped. How deep is the lake?

Explanation / Answer

Velocity of the ball before touching the water is

V=2gh

=[2*9.8*30]= 24.2 m/s

The depth of the lake is

D=v*t =24.2*10=240.2 m

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