A.) Calculate the approximate radius of a sodium nucleus, 23 11 Na. (You can ign

Question

A.) Calculate the approximate radius of a sodium nucleus, 2311Na. (You can ignore the mass defect in this calculation and simply take the mass of the nucleus to be equal to the sum of the masses of its nucleons.)

B.) Calculate the approximate volume of a sodium nucleus, 2311Na. (You can ignore the mass defect in this calculation and simply take the mass of the nucleus to be equal to the sum of the masses of its nucleons.)

C.) Calculate the approximate density (in kg/m3) of a sodium nucleus, 2311Na. (You can ignore the mass defect in this calculation and simply take the mass of the nucleus to be equal to the sum of the masses of its nucleons.)

Explanation / Answer

A value of 23 N11 = 23

R =Ro A^1/3

Ro =1.25*10^-15 m

R = (1.25*10^-15)(23)^1/3

R = 3.555*10^-15 m

B) V = (4/3)pi*R^3

V = (4*3.14/3)(3.555*10^-15)^3

V =1.88*10^-43 m^3

C) m =23 u = 23*1.66*10^-27 kg

density = mass/volume = 23*1.66*10^-27/(1.88*10^-43)

d = 2.031*10^17 kg/m^3

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