Consider two charged particles, one held at a fixed position and the second able
ID: 1515772 • Letter: C
Question
Consider two charged particles, one held at a fixed position and the second able to move freely. The second particle is released from rest a distance r away from the fixed particle and is observed to be moving directly away from the fixed particle at velocity 10 m/s at the moment the distance between the two charged particles is 2r. What is the maximum velocity that will be reached by the moving particle if you watch it long enough? 10 m/s 14 m/s 20 m/s It will keep accelerating and reach an infinite velocity 15. The following drawing represents the electric field lines for two point charges.What can be said about these two charges? The left charge is negative and the right charge positive The left charge is positive and the right charge negative Both charges are positive Both charges are negativeExplanation / Answer
Total energy initially
U1 = 1/2*m*v^2 + Energy store in the system.
=(1/2)*m*(10^2) + k*q*Q/(2r) ...(1)
Total energy of the system finally
U2 = U1
v= root (2/m[(1/2)*m*(10^2) + k*q*Q/(2r)])
Using this equation we can find final velocity of the moving charge. m, q, Q, r are required value for it.
2.
Left charge is +ve, and right charge is -ve.