An antenna is guyed by three cables as shown. Knowing that the tension in cable

Question

An antenna is guyed by three cables as shown. Knowing that the tension in cable AD is 1.35 kN, replace the force exerted at A by cable AD with an equivalent force-couple system at the center O of the base of the antenna. A 110-N force acting in a vertical plane parallel to the yz plane is applied to the 220-mm-long horizontal handle AB of a socket wrench. Replace the force with an equivalent force-couple system at the origin O of the coordinate system. An eccentric, compressive 1220-N force P is applied to the end of a cantilever beam. Replace P with an equivalent force-couple system at G.

Explanation / Answer

We have : B =F P F
where 110 N[ -(sin15 )i + (cos15 )j ]
= -(28.470 N)i +(106.252 N)j
  
We have

[(0.22cos35 )i + (0.15)j +(0.22sin 35 )k ] m
(0.180213 m)i +(0.15 m)j +(0.126187 m)k
Hence
M = (12.35 N / m) i - (19.16 N / m) j - (5.13 N / m) k

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