Particle A of charge 3.35 104 C is at the origin, particle B of charge 6.05 104

Question

Particle A of charge 3.35 104 C is at the origin, particle B of charge 6.05 104 C is at (4.26 m, 0) and particle C of charge 1.10 104 C is at (0, 3.16 m). (a) What is the x-component of the electric force exerted by A on C? N (b) What is the y-component of the force exerted by A on C? N (c) Find the magnitude of the force exerted by B on C. N (d) Calculate the x-component of the force exerted by B on C. N (e) Calculate the y-component of the force exerted by B on C. N (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. N (g) Repeat part (f) for the y-component. N (h) Find the magnitude and direction of the resultant electric force acting on C. magnitude N direction ° counterclockwise from the +x-axis

Explanation / Answer

a) x-component of the electric force exerted by A on C will be Zero

b) y-component of the force exerted by A on C

Fy = kQaQc / Rac^2 = 33.2 N

c) magnitude of the force exerted by B on C

Rbc = sqrt(4.26^2 + 3.16^2) = 5.3 m

F = 21.3 N

d) x-component of the force exerted by B on C

Fx = Fcos(theta) = 21.3*(4.26/5.3) = 17.12 N

e) y-component of the force exerted by B on C

Fy = Fsin(theta) = 21.3*(3.16/5.3) = 12.7 N

f) resultant x-component of the electric force acting on C = 17.12 N

g) resultant y-component of the electric force acting on C = 33.2 + 12.7 = 45.9 N

h)  magnitude and direction of the resultant electric force acting on C

Fnet = 17.12 i + 45.9 j

magnitude = 49 N

direction = 69.5 degree from +x axis

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