I need the answer as soon as possible please Three charged particles are at the
ID: 1523229 • Letter: I
Question
I need the answer as soon as possible please
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 3.00 mu C, and L = 0.850 m.) Calculate the electric field at the position of charge q due to the 7.00-mu C and -4.00-mu C charges. Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. kN/C i^+ Does the -4.00-mu C charge contribute to the y component of the field at the origin? kN/C j^Use your answer to part (a) to determine the force on charge q. If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN i^+ If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN j^Explanation / Answer
Q2) Magnitude of force on Q1 due to Q3 = F = k*Q1*Q3/1.3² Magnitude of force on Q1 due to Q2 = F = k*Q2*Q1/1.3² Now you must add up the components in vector form: Fx = Fcos(60°) - Fcos(60°) Fy = Fsin(60°) + Fsin(60°) 60° because it's an equilateral triangle. You'll notice the signs of the forces - both F and F are negative, and only the x-component of the F force is positive. 1) electric field you can get by the equation E=(1/4*3.14*epsilon nought)*(charge due to electric field)/distandistance from charge to point.