IF YOU CHOOSE TO ANSWER ONE OF MY QUESTIONS PLEASE CONSIDER THE FOLLOWING FIRST:
ID: 1523442 • Letter: I
Question
IF YOU CHOOSE TO ANSWER ONE OF MY QUESTIONS PLEASE CONSIDER THE FOLLOWING FIRST: I am trying to learn from all you smart physics folk, so please help me learn from you! :)
1.) Please include what each given variable in the question is identified as in words and the symbol please
2.) Please include all equations used, and mark as EQ: with proper identification of what each variable is in the equation, and briefly explain why you chose this equation.
3.) Please include a step by step process of how this question was solved, 1, 2, 3, etc. and box/cirlce the final answer and include the units.
4.) Please include a picture for this one please!
Q#2: A particle starts from the origin at t=0 with a velocity of 6.0 i hat m/s and moves in the x-y plane with a constant acceleration of (-2.0 i hat+ 4.0 j hat) m/s^2
At the instant the particle achieves its maximum positive x coordinate, how far is it from the origin?
A particle starts from the origin at t = 0 with a velocity of 6.0 m/s and moves in the xy plane
with a constant acceleration of (2.0 + 4.0 ) m/s2. At the instant the particle achieves its
maximum positive x coordinate, how far is it from the origin?
Explanation / Answer
given that
u = 6 i m/s
a = -2 i + 4 j m/s^2
v = u +at in x direction
put v = 0
0 = 6 - 2*t
t = 3 sec
Sx = 1/2*ax*t^2 = 0.5*(-2)*3*3 = -9 m
Sy = 1/2*ay*t^2 = 0.5*4*3*3 = 18 m
distance from the origin S =sqrt(Sx^2 + Sy^2)
S = sqrt(81 + 324)
S = 20.12 m