In the figure below, a nonconducting rod of length L = 7.15 cm has charge q = 4.

Question

In the figure below, a nonconducting rod of length L = 7.15 cm has charge q = 4.36 fC uniformly distributed along its length.

(a) What is the linear charge density of the rod?
-6.1 x 10^-14 C/m

(b) What is the magnitude of the electric field at point P, a distance a = 12.0 cm from the end of the rod?
N/C

(c) What is its direction?
180 degrees (counterclockwise from the positive x axis)

(d) What is the electric field magnitude produced at distance a = 50 m by the rod?
N/C

(e) Repeat part (d) for a particle of charge q = 4.36 fC that replaces the rod.
N/C

Explanation / Answer

a) as given: length L = 7.15 cm and charge q = 4.36 fC

so, the linear charge density of the rod = (-4.36x10^-15 C) / (7.15X10^-2 m) = -6.097 X10^-14 C/m

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